LeetCode 2122: Recover the Original Array Solution

Master LeetCode problem 2122 (Recover the Original Array), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2122. Recover the Original Array

Problem Explanation

Explanation:

To recover the original array, we need to find the value of k and then reconstruct the array arr based on the values in lower and higher. We can do this by finding the minimum value in lower and the maximum value in higher, which will give us the range of values that k can take.

  1. Find the minimum value in lower and maximum value in higher.
  2. Calculate k as the difference between the maximum value in higher and the minimum value in lower.
  3. Construct the original array arr by adding k to each value in lower.

Time Complexity: O(n)
Space Complexity: O(n)

:

Solution Code

class Solution {
    public int[] recoverArray(int[] nums) {
        Arrays.sort(nums);
        int n = nums.length / 2;
        int k = nums[nums.length - 1] - nums[0];
        int[] arr = new int[n];
        for (int i = 0; i < n; i++) {
            arr[i] = nums[i] + k;
        }
        return arr;
    }
}

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