LeetCode 2130: Maximum Twin Sum of a Linked List Solution

Master LeetCode problem 2130 (Maximum Twin Sum of a Linked List), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2130. Maximum Twin Sum of a Linked List

Medium

Linked List Two Pointers Stack

Problem Explanation

Explanation

To find the maximum twin sum of the given linked list, we iterate through the list and pair up nodes with their twins. We keep track of the maximum twin sum found so far and update it if we find a higher twin sum. We can do this by traversing the linked list and comparing the sum of each pair of nodes with their twins.

Initialize variables maxTwinSum to store the maximum twin sum found so far and currentNode to traverse the linked list.
Traverse the linked list while currentNode and its twin are not null.
Compare the sum of the current node's value and its twin's value with maxTwinSum. If it's greater, update maxTwinSum.
Move to the next pair of nodes.
Return maxTwinSum as the final result.

Time complexity: O(n) where n is the number of nodes in the linked list. Space complexity: O(1)

Solution Code

class ListNode {
    int val;
    ListNode next;
    ListNode(int val) {
        this.val = val;
    }
}

public int maxTwinSum(ListNode head) {
    int maxTwinSum = 0;
    ListNode currentNode = head;
    
    while (currentNode != null && currentNode.next != null) {
        int twinSum = currentNode.val + currentNode.next.val;
        maxTwinSum = Math.max(maxTwinSum, twinSum);
        currentNode = currentNode.next.next;
    }
    
    return maxTwinSum;
}

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