LeetCode 2132: Stamping the Grid Solution
Master LeetCode problem 2132 (Stamping the Grid), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
2132. Stamping the Grid
Problem Explanation
Explanation:
To solve this problem, we can use a greedy approach. We start by trying to stamp the grid starting from each empty cell. For each empty cell, we check if it is possible to stamp the grid by aligning the stamp with the current empty cell. If we can stamp the grid starting from any empty cell, then it is possible to fit the stamps.
Algorithm:
- Create a helper function
canStampthat checks if we can stamp the grid starting from a given position. - Iterate through all empty cells in the grid.
- For each empty cell, try to stamp the grid starting from that cell using the
canStampfunction. - If we can successfully stamp the grid from any empty cell, return true. Otherwise, return false.
Time Complexity: O(mn(m*n)) where m and n are the dimensions of the grid. Space Complexity: O(1)
:
Solution Code
class Solution {
public boolean canStamp(int[][] grid, int[][] stamp, int row, int col) {
boolean stamped = false;
for (int i = 0; i < stamp.length; i++) {
for (int j = 0; j < stamp[0].length; j++) {
if (stamp[i][j] == 0) {
if (grid[row + i][col + j] == 1) {
return false;
}
stamped = true;
grid[row + i][col + j] = 1;
}
}
}
return stamped;
}
public boolean canStampTheGrid(int[][] grid, int stampHeight, int stampWidth) {
int m = grid.length, n = grid[0].length;
int[][] stamp = new int[stampHeight][stampWidth];
Arrays.fill(stamp[0], 1);
boolean stamped = false;
while (!stamped) {
stamped = true;
for (int i = 0; i <= m - stampHeight; i++) {
for (int j = 0; j <= n - stampWidth; j++) {
if (canStamp(grid, stamp, i, j)) {
stamped = false;
}
}
}
}
for (int i = 0; i < m; i++) {
for (int j = 0; j < n; j++) {
if (grid[i][j] == 0) {
return false;
}
}
}
return true;
}
}Try It Yourself
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