LeetCode 2136: Earliest Possible Day of Full Bloom Solution

Master LeetCode problem 2136 (Earliest Possible Day of Full Bloom), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2136. Earliest Possible Day of Full Bloom

Hard

Array Greedy Sorting

Problem Explanation

Explanation

To solve this problem, we need to simulate the process of planting and growing the seeds day by day until all seeds have bloomed. We can keep track of the days each seed is planted and the days it takes to grow. We will iterate through the days, planting and growing the seeds accordingly, until all seeds have bloomed.

We will create a priority queue to keep track of the seeds that are ready to grow on each day.
We will create a variable to store the current day.
We will iterate through the days until all seeds have bloomed, checking and updating the status of each seed on each day.

Time Complexity: O(n log n) - where n is the number of seeds
Space Complexity: O(n)

Solution Code

import java.util.PriorityQueue;

class Solution {
    public int earliestDayToFullBloom(int[] plantTime, int[] growTime) {
        int n = plantTime.length;
        PriorityQueue<int[]> pq = new PriorityQueue<>((a, b) -> a[0] - b[0]);
        int day = 0;

        for (int i = 0; i < n; i++) {
            pq.offer(new int[]{plantTime[i], growTime[i]});
        }

        while (!pq.isEmpty()) {
            int[] seed = pq.poll();
            day = Math.max(day + seed[0], seed[1]);
        }

        return day;
    }
}

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