LeetCode 2143: Choose Numbers From Two Arrays in Range Solution

Master LeetCode problem 2143 (Choose Numbers From Two Arrays in Range), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2143. Choose Numbers From Two Arrays in Range

Hard

Array Dynamic Programming

Problem Explanation

Explanation:

Given two arrays nums1 and nums2, and an integer start, we need to find the number of ways to choose one integer from each array such that the chosen integers are in the range [start, start + 3].

Algorithmic Idea:

Initialize a counter count to 0.
For each integer num1 in nums1, and each integer num2 in nums2, check if num1 and num2 fall in the range [start, start + 3].
If num1 and num2 fall in the range, increment count.
Return the final count as the result.

Time Complexity:

The time complexity of this algorithm is O(n * m), where n is the length of nums1 and m is the length of nums2.

Space Complexity:

The space complexity of this algorithm is O(1) as we are not using any extra space.

: :

Solution Code

public int countRange(int[] nums1, int[] nums2, int start) {
    int count = 0;
    for (int num1 : nums1) {
        for (int num2 : nums2) {
            if (num1 >= start && num1 <= start + 3 && num2 >= start && num2 <= start + 3) {
                count++;
            }
        }
    }
    return count;
}

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