LeetCode 2154: Keep Multiplying Found Values by Two Solution

Master LeetCode problem 2154 (Keep Multiplying Found Values by Two), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2154. Keep Multiplying Found Values by Two

Problem Explanation

Explanation

To solve this problem, we iterate through the array nums checking if the current value is equal to original. If it is found, we update original to be twice its value. We repeat this process until we either don't find the current original value in nums or reach the end of the array. Finally, we return the updated original.

  • Time complexity: O(n), where n is the number of elements in the array nums.
  • Space complexity: O(1).

Solution Code

class Solution {
    public int keepMultiplyingFoundValuesByTwo(int[] nums, int original) {
        for (int num : nums) {
            if (num == original) {
                original *= 2;
            } else {
                break;
            }
        }
        return original;
    }
}

Try It Yourself

Loading code editor...

Related LeetCode Problems

Frequently Asked Questions

How to solve LeetCode 2154 (Keep Multiplying Found Values by Two)?

This page provides optimized solutions for LeetCode problem 2154 (Keep Multiplying Found Values by Two) in Java, C++, and Python, along with a detailed explanation and an interactive code editor to test your code.

What is the time complexity of LeetCode 2154 (Keep Multiplying Found Values by Two)?

The time complexity for LeetCode 2154 (Keep Multiplying Found Values by Two) varies by solution. Check the detailed explanation section for specific complexities in Java, C++, and Python implementations.

Can I run code for LeetCode 2154 on DevExCode?

Yes, DevExCode provides an interactive code editor where you can write, test, and run your code for LeetCode 2154 in Java, C++, or Python.

Back to LeetCode Solutions