LeetCode 2155: All Divisions With the Highest Score of a Binary Array Solution
Master LeetCode problem 2155 (All Divisions With the Highest Score of a Binary Array), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
2155. All Divisions With the Highest Score of a Binary Array
Problem Explanation
Explanation
To solve this problem, we need to iterate through each index of the binary array and calculate the division score at that index. The division score at an index i is the sum of the number of zeros to the left of index i and the number of ones to the right of index i. We will keep track of the maximum division score encountered so far and all the indices that have this maximum score.
- Initialize variables
maxScoreto store the maximum division score, andresultto store indices with the maximum score. - Iterate through each index
ifrom 0 ton. - Calculate the division score at index
i. - If the score at index
iis greater thanmaxScore, updatemaxScoreand clearresultto only include the current indexi. - If the score at index
iis equal tomaxScore, addito the list of indices inresult. - Return the list of indices with the highest division score.
Time Complexity: O(n) where n is the length of the input array. Space Complexity: O(1) since we are only using constant extra space.
Solution Code
class Solution {
public List<Integer> maxScore(int[] nums) {
int n = nums.length;
int maxScore = Integer.MIN_VALUE;
List<Integer> result = new ArrayList<>();
for (int i = 0; i <= n; i++) {
int score = countZeros(nums, 0, i - 1) + countOnes(nums, i, n - 1);
if (score > maxScore) {
maxScore = score;
result.clear();
result.add(i);
} else if (score == maxScore) {
result.add(i);
}
}
return result;
}
private int countZeros(int[] nums, int start, int end) {
int count = 0;
for (int i = start; i <= end; i++) {
if (nums[i] == 0) {
count++;
}
}
return count;
}
private int countOnes(int[] nums, int start, int end) {
int count = 0;
for (int i = start; i <= end; i++) {
if (nums[i] == 1) {
count++;
}
}
return count;
}
}Try It Yourself
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