LeetCode 2160: Minimum Sum of Four Digit Number After Splitting Digits Solution
Master LeetCode problem 2160 (Minimum Sum of Four Digit Number After Splitting Digits), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
Problem Explanation
Explanation
To solve this problem, we need to find all possible ways to split the four digits into two separate numbers and calculate the sum of those two numbers. The key idea is to try all possible ways to split the digits and find the pair that gives the minimum sum.
Algorithm
- Iterate through all possible ways to split the four digits into two parts.
- Calculate the sum of the two parts.
- Keep track of the minimum sum found so far.
- Return the minimum sum as the result.
Time Complexity
The time complexity of this algorithm is O(1) since we are iterating through a constant number of possibilities.
Space Complexity
The space complexity of this algorithm is O(1) as we are not using any additional data structures.
Solution Code
class Solution {
public int minSum(int num) {
int[] digits = new int[4];
for (int i = 3; i >= 0; i--) {
digits[i] = num % 10;
num /= 10;
}
int minSum = Integer.MAX_VALUE;
for (int i = 0; i < 4; i++) {
for (int j = i + 1; j < 4; j++) {
int num1 = digits[0] * 10 + digits[1];
int num2 = digits[2] * 10 + digits[3];
int sum = num1 + num2;
minSum = Math.min(minSum, sum);
}
}
return minSum;
}
}Try It Yourself
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How to solve LeetCode 2160 (Minimum Sum of Four Digit Number After Splitting Digits)?
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What is the time complexity of LeetCode 2160 (Minimum Sum of Four Digit Number After Splitting Digits)?
The time complexity for LeetCode 2160 (Minimum Sum of Four Digit Number After Splitting Digits) varies by solution. Check the detailed explanation section for specific complexities in Java, C++, and Python implementations.
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