LeetCode 2170: Minimum Operations to Make the Array Alternating Solution

Master LeetCode problem 2170 (Minimum Operations to Make the Array Alternating), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2170. Minimum Operations to Make the Array Alternating

Medium

Array Hash Table Greedy Counting

Problem Explanation

Explanation

To make the array alternating, we need to ensure that every two consecutive elements are different. We can achieve this by iterating through the array and checking if the current element is the same as the previous two elements. If it is the same, we need to change it to a different number. We can achieve this by keeping track of the number of operations needed to change the element at each index.

Algorithm

Initialize a variable ops to store the total number of operations needed.
Iterate through the array starting from index 2.
For each element at index i, if it is the same as the previous two elements, increment ops by 1 and update the current element to a different number.
Return the total number of operations ops.

Time Complexity

The time complexity of this algorithm is O(n) where n is the number of elements in the array.

Space Complexity

The space complexity of this algorithm is O(1) as we are using a constant amount of extra space.

Solution Code

class Solution {
    public int minOperations(int[] nums) {
        int ops = 0;
        for (int i = 2; i < nums.length; i++) {
            if (nums[i] == nums[i - 2]) {
                ops++;
                nums[i] = nums[i] == nums[i - 1] ? nums[i] + 1 : nums[i - 1];
            }
        }
        return ops;
    }
}

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