LeetCode 2178: Maximum Split of Positive Even Integers Solution

Master LeetCode problem 2178 (Maximum Split of Positive Even Integers), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2178. Maximum Split of Positive Even Integers

Medium

Math Backtracking Greedy

Problem Explanation

Explanation

To solve this problem, we can start by iterating from 2 to finalSum (inclusive) and greedily select the largest even number possible until the remaining sum becomes less than the next even number. This way, we can maximize the number of unique positive even integers in the split. We need to keep track of the remaining sum and the selected even integers. If the remaining sum reaches 0, we have found a valid split.

Algorithmic Idea:
1. Start iterating from 2 to finalSum.
2. At each step, check if the current even number can be included in the split without exceeding the remaining sum.
3. If yes, update the remaining sum and include the current even number in the split.
4. Continue this process until the remaining sum becomes 0 or no valid split is possible.
5. Return the list of selected even integers if a valid split is found.
Time Complexity: O(N), where N is the value of finalSum.
Space Complexity: O(1) since we only use a constant amount of extra space.

Solution Code

class Solution {
    public List<Integer> splitIntoMaximumEvenNumbers(int finalSum) {
        List<Integer> result = new ArrayList<>();
        int remainingSum = finalSum;
        
        for (int num = 2; num <= finalSum; num += 2) {
            if (remainingSum >= num) {
                result.add(num);
                remainingSum -= num;
            } else {
                break;
            }
        }
        
        if (remainingSum == 0) {
            return result;
        } else {
            return new ArrayList<>();
        }
    }
}

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