LeetCode 2180: Count Integers With Even Digit Sum Solution
Master LeetCode problem 2180 (Count Integers With Even Digit Sum), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
2180. Count Integers With Even Digit Sum
Problem Explanation
Explanation
To solve this problem, we iterate through all numbers from 1 to num. For each number, we calculate the sum of its digits and check if the sum is even. If it is even, we increment a counter. Finally, we return the counter as the result.
Time complexity: O(n) Space complexity: O(1)
Solution Code
class Solution {
public int countIntegersWithEvenDigitSum(int num) {
int count = 0;
for (int i = 1; i <= num; i++) {
int digitSum = 0;
int n = i;
while (n > 0) {
digitSum += n % 10;
n /= 10;
}
if (digitSum % 2 == 0) {
count++;
}
}
return count;
}
}Try It Yourself
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