LeetCode 2186: Minimum Number of Steps to Make Two Strings Anagram II Solution

Master LeetCode problem 2186 (Minimum Number of Steps to Make Two Strings Anagram II), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2186. Minimum Number of Steps to Make Two Strings Anagram II

Medium

Hash Table String Counting

Problem Explanation

Explanation:

To solve this problem, we can use the concept of anagram by counting the frequency of characters in both strings s and t. We can then find the difference between the frequencies of characters. The minimum number of steps required to make s and t anagrams of each other would be the sum of absolute differences of frequencies of characters in both strings.

Create an array to store the frequency of characters for both strings s and t.
Iterate through both strings and update the frequency array accordingly.
Calculate the absolute difference in frequencies for each character.
Sum up all the absolute differences to get the minimum number of steps required. :

Solution Code

class Solution {
    public int minSteps(String s, String t) {
        int[] frequency = new int[26];
        
        for (char c : s.toCharArray()) {
            frequency[c - 'a']++;
        }
        
        for (char c : t.toCharArray()) {
            frequency[c - 'a']--;
        }
        
        int steps = 0;
        for (int count : frequency) {
            steps += Math.abs(count);
        }
        
        return steps;
    }
}

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