LeetCode 2208: Minimum Operations to Halve Array Sum Solution

Master LeetCode problem 2208 (Minimum Operations to Halve Array Sum), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2208. Minimum Operations to Halve Array Sum

Problem Explanation

Explanation:

To solve this problem, we need to find the minimum number of operations required to reduce the sum of the array by at least half. We can achieve this by iteratively selecting the maximum number in the array and reducing it to half until the sum of the array is less than half of the original sum.

  1. Sort the input array in descending order.
  2. Calculate the initial sum of the array.
  3. Initialize a variable target as half of the initial sum.
  4. Initialize a variable operations to count the number of operations.
  5. Iterate through the sorted array and for each element:
    • If the current element is greater than or equal to target, divide it by 2 and increment the operations count.
    • Update the target as half of the updated sum.
  6. Return the total number of operations.

Time Complexity: O(n log n) where n is the number of elements in the array due to sorting. Space Complexity: O(1)

:

Solution Code

class Solution {
    public int minOperations(int[] nums) {
        Arrays.sort(nums);
        int n = nums.length;
        int sum = Arrays.stream(nums).sum();
        int target = sum / 2;
        int operations = 0;
        
        for (int i = n - 1; i >= 0; i--) {
            if (nums[i] >= target) {
                operations++;
                nums[i] /= 2;
                sum = Arrays.stream(nums).sum();
                target = sum / 2;
            } else {
                break;
            }
        }
        
        return operations;
    }
}

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