LeetCode 2216: Minimum Deletions to Make Array Beautiful Solution
Master LeetCode problem 2216 (Minimum Deletions to Make Array Beautiful), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
Problem Explanation
Explanation
To make the array beautiful, we need to ensure that the length is even and no adjacent elements are the same. We can achieve this by iterating through the array and counting the number of deletions needed to fix the violations of the beauty condition. We can then return the minimum number of deletions required.
Algorithm:
- Initialize a variable
deletionsto 0. - Iterate through the array starting from the second element (index 1) and check if the current element is equal to the previous element. If it is, increment
deletions. - After the loop, return
deletions.
Time Complexity: O(n) where n is the length of the array. Space Complexity: O(1)
Solution Code
class Solution {
public int minDeletions(int[] nums) {
int deletions = 0;
for (int i = 1; i < nums.length; i++) {
if (nums[i] == nums[i - 1]) {
deletions++;
}
}
return deletions;
}
}Try It Yourself
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