LeetCode 2262: Total Appeal of A String Solution

Master LeetCode problem 2262 (Total Appeal of A String), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2262. Total Appeal of A String

Hard

Hash Table String Dynamic Programming

Problem Explanation

Explanation

To solve this problem, we can iterate through all substrings of the input string s and calculate the appeal of each substring. We can do this by maintaining a frequency array to count the occurrences of each character within the current substring. Then, we iterate over all possible substrings of different lengths and calculate the total appeal.

Initialize a variable totalAppeal to store the sum of appeals of all substrings.
Iterate over all possible starting positions i from 0 to n-1 where n is the length of the input string.
For each starting position i, iterate over all possible ending positions j from i to n-1.
For each substring from position i to j, maintain a frequency array to count the occurrences of each character.
Calculate the appeal of the current substring as the number of unique characters in the frequency array.
Update the totalAppeal by adding the appeal of the current substring.
Finally, return the totalAppeal.

The time complexity of this approach is O(n^2) where n is the length of the input string s. The space complexity is O(26) for the frequency array, which is constant.

Solution Code

class Solution {
    public int totalAppeal(String s) {
        int totalAppeal = 0;
        int n = s.length();

        for (int i = 0; i < n; i++) {
            int[] freq = new int[26];
            for (int j = i; j < n; j++) {
                freq[s.charAt(j) - 'a']++;
                int appeal = 0;
                for (int k = 0; k < 26; k++) {
                    if (freq[k] > 0) {
                        appeal++;
                    }
                }
                totalAppeal += appeal;
            }
        }

        return totalAppeal;
    }
}

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