LeetCode 2277: Closest Node to Path in Tree Solution
Master LeetCode problem 2277 (Closest Node to Path in Tree), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
2277. Closest Node to Path in Tree
Problem Explanation
Explanation:
Given a binary tree and a list of nodes representing a path, we need to find the node in the tree that is closest to the path. The distance between two nodes is defined as the number of edges on the path between them.
To solve this problem, we can traverse the tree and for each node, calculate the distance to each node in the path. We can keep track of the minimum distance encountered so far and the node corresponding to that minimum distance.
Algorithm:
- Initialize a variable
minDistanceto infinity andclosestNodeto null. - Perform a depth-first search traversal of the tree.
- For each node encountered during the traversal, calculate the distance to each node in the path.
- Update
minDistanceandclosestNodeif a closer node is found. - Return the
closestNodeat the end of the traversal.
Time Complexity:
- The time complexity of this approach is O(N*M), where N is the number of nodes in the tree and M is the number of nodes in the path.
Space Complexity:
- The space complexity of this approach is O(H), where H is the height of the tree.
:
Solution Code
class TreeNode {
int val;
TreeNode left;
TreeNode right;
TreeNode(int x) { val = x; }
}
class Solution {
private TreeNode closestNode;
private int minDistance = Integer.MAX_VALUE;
public TreeNode closestNodeToPath(TreeNode root, List<TreeNode> path) {
dfs(root, path, 0);
return closestNode;
}
private void dfs(TreeNode node, List<TreeNode> path, int depth) {
if (node == null) return;
for (TreeNode target : path) {
int distance = getDistance(node, target);
if (distance < minDistance) {
minDistance = distance;
closestNode = node;
}
}
dfs(node.left, path, depth + 1);
dfs(node.right, path, depth + 1);
}
private int getDistance(TreeNode node1, TreeNode node2) {
// Calculate distance between two nodes
}
}Try It Yourself
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