LeetCode 2280: Minimum Lines to Represent a Line Chart Solution

Master LeetCode problem 2280 (Minimum Lines to Represent a Line Chart), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2280. Minimum Lines to Represent a Line Chart

Medium

Array Math Geometry Sorting Number Theory

Problem Explanation

Explanation:

To solve this problem, we can iterate through the given array of stock prices and find the points where the price changes. Whenever the price changes, we increment the count of lines needed to represent the line chart. The minimum number of lines needed will be the count of these points where the price changes.

Initialize a variable lines to store the count of lines needed.
Iterate through the stock prices array and compare the price of the current day with the price of the previous day.
If the price changes, increment the lines by 1.
Return the final value of lines as the minimum number of lines needed.

Time Complexity:

The time complexity of this algorithm is O(n) where n is the number of stock prices.

Space Complexity:

The space complexity of this algorithm is O(1) as we are using only a constant amount of extra space.

Solution Code

class Solution {
    public int minLines(int[][] stockPrices) {
        if (stockPrices.length == 0) {
            return 0;
        }
        
        int lines = 1;
        for (int i = 1; i < stockPrices.length; i++) {
            if (stockPrices[i][1] != stockPrices[i - 1][1]) {
                lines++;
            }
        }
        
        return lines;
    }
}

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What is the time complexity of LeetCode 2280 (Minimum Lines to Represent a Line Chart)?

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