LeetCode 2283: Check if Number Has Equal Digit Count and Digit Value Solution
Master LeetCode problem 2283 (Check if Number Has Equal Digit Count and Digit Value), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
2283. Check if Number Has Equal Digit Count and Digit Value
Problem Explanation
Explanation:
We can solve this problem by iterating through the given string num and checking if the count of each digit at index i matches the value of the digit itself. If we find any mismatch, we can return false immediately. If we iterate through the entire string without finding any discrepancies, we return true.
Algorithmic Idea:
- Iterate through the string
numfrom index 0 to n-1. - For each digit at index
i, check if the count of that digit in the entire string matches the digit itself. - If there is a mismatch, return false.
- If we finish the loop without finding any mismatches, return true.
Time Complexity:
The time complexity of this solution is O(n), where n is the length of the input string num.
Space Complexity:
The space complexity of this solution is O(1) as we are using a constant amount of extra space. :
Solution Code
class Solution {
public boolean hasEqualDigitCountAndValue(String num) {
for (int i = 0; i < num.length(); i++) {
int count = 0;
for (int j = 0; j < num.length(); j++) {
if (num.charAt(j) - '0' == i) {
count++;
}
}
if (count != num.charAt(i) - '0') {
return false;
}
}
return true;
}
}Try It Yourself
Loading code editor...
Related LeetCode Problems
Frequently Asked Questions
How to solve LeetCode 2283 (Check if Number Has Equal Digit Count and Digit Value)?
This page provides optimized solutions for LeetCode problem 2283 (Check if Number Has Equal Digit Count and Digit Value) in Java, C++, and Python, along with a detailed explanation and an interactive code editor to test your code.
What is the time complexity of LeetCode 2283 (Check if Number Has Equal Digit Count and Digit Value)?
The time complexity for LeetCode 2283 (Check if Number Has Equal Digit Count and Digit Value) varies by solution. Check the detailed explanation section for specific complexities in Java, C++, and Python implementations.
Can I run code for LeetCode 2283 on DevExCode?
Yes, DevExCode provides an interactive code editor where you can write, test, and run your code for LeetCode 2283 in Java, C++, or Python.