LeetCode 2284: Sender With Largest Word Count Solution

Master LeetCode problem 2284 (Sender With Largest Word Count), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2284. Sender With Largest Word Count

Medium

Array Hash Table String Counting

Problem Explanation

Explanation

To solve this problem, we can iterate through the messages and keep track of the word count for each sender using a HashMap. After calculating the word count for each sender, we can then find the sender with the largest word count. In case of a tie, we return the sender with the lexicographically largest name.

Create a HashMap to store the word count for each sender.
Iterate through the messages array and split each message into words.
Update the word count for the sender of the current message.
Find the sender with the largest word count. If there is a tie, return the sender with the lexicographically largest name.

Solution Code

import java.util.*;

class Solution {
    public String largestSender(String[] messages, String[] senders) {
        Map<String, Integer> wordCount = new HashMap<>();
        
        for (int i = 0; i < messages.length; i++) {
            String sender = senders[i];
            String[] words = messages[i].split(" ");
            wordCount.put(sender, wordCount.getOrDefault(sender, 0) + words.length);
        }
        
        String largestSender = "";
        int maxCount = 0;
        
        for (Map.Entry<String, Integer> entry : wordCount.entrySet()) {
            if (entry.getValue() > maxCount || (entry.getValue() == maxCount && entry.getKey().compareTo(largestSender) > 0)) {
                maxCount = entry.getValue();
                largestSender = entry.getKey();
            }
        }
        
        return largestSender;
    }
}

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