LeetCode 2306: Naming a Company Solution

Master LeetCode problem 2306 (Naming a Company), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

Problem Explanation

Explanation

To solve this problem, we can iterate through all pairs of distinct strings from the given array ideas. For each pair, we swap the first letters of the two strings and check if the resulting company name is unique in the original array. If it is unique, we increment a counter to count the number of valid company names. Finally, we return the count of valid company names.

  • Time complexity: O(n^2) where n is the number of strings in the ideas array.
  • Space complexity: O(n) to store the set of original strings.

Solution Code

import java.util.HashSet;
import java.util.Set;

class Solution {
    public int namingCompany(String[] ideas) {
        Set<String> originalIdeas = new HashSet<>();
        for (String idea : ideas) {
            originalIdeas.add(idea);
        }
        
        int count = 0;
        for (int i = 0; i < ideas.length; i++) {
            for (int j = i + 1; j < ideas.length; j++) {
                String ideaA = ideas[i];
                String ideaB = ideas[j];
                
                String newName = ideaB.charAt(0) + ideaA.substring(1) + " " + ideaA.charAt(0) + ideaB.substring(1);
                if (!originalIdeas.contains(newName)) {
                    count++;
                }
            }
        }
        
        return count;
    }
}

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