LeetCode 2312: Selling Pieces of Wood Solution
Master LeetCode problem 2312 (Selling Pieces of Wood), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
2312. Selling Pieces of Wood
Problem Explanation
Explanation:
To solve this problem, we can use dynamic programming. We will create a 2D DP array where DP[i][j] represents the maximum amount of money that can be earned by cutting an i x j piece of wood. We will iterate through all possible cuts and update the DP array accordingly. Finally, the answer will be stored at DP[m][n].
- Initialize the DP array with zeros.
- Iterate through all possible cuts:
- For each cut, check if cutting vertically or horizontally would yield a higher profit.
- Update the DP array with the maximum profit.
- Return the value stored at DP[m][n].
Time Complexity: O(m^2 * n^2) where m and n are the dimensions of the wood piece.
Space Complexity: O(m * n) for the DP array.
:
Solution Code
class Solution {
public int maxProfit(int m, int n, int[][] prices) {
int[][] dp = new int[m + 1][n + 1];
for (int i = 1; i <= m; i++) {
for (int j = 1; j <= n; j++) {
for (int[] price : prices) {
int h = price[0];
int w = price[1];
int p = price[2];
if (h <= i) {
dp[i][j] = Math.max(dp[i][j], dp[i - h][j] + dp[h][j] + p);
}
if (w <= j) {
dp[i][j] = Math.max(dp[i][j], dp[i][j - w] + dp[i][w] + p);
}
}
}
}
return dp[m][n];
}
}Try It Yourself
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