LeetCode 2357: Make Array Zero by Subtracting Equal Amounts Solution
Master LeetCode problem 2357 (Make Array Zero by Subtracting Equal Amounts), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
2357. Make Array Zero by Subtracting Equal Amounts
Problem Explanation
Explanation
To solve this problem, we need to find the minimum number of operations required to make every element in the array equal to 0. The key idea is to keep track of the smallest non-zero element in the array and subtract that value from all positive elements in each operation until all elements become 0.
- Find the smallest non-zero element in the array.
- Subtract this value from all positive elements in each operation until all elements become 0.
- Count the number of operations performed.
Time complexity: O(n) where n is the number of elements in the array. Space complexity: O(1)
Solution Code
class Solution {
public int minOperations(int[] nums) {
int minNonZero = Integer.MAX_VALUE;
int count = 0;
for (int num : nums) {
if (num > 0 && num < minNonZero) {
minNonZero = num;
}
}
for (int i = 0; i < nums.length; i++) {
if (nums[i] > 0) {
count += (nums[i] / minNonZero);
if (nums[i] % minNonZero != 0) {
count++;
}
}
}
return count;
}
}Try It Yourself
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