LeetCode 2364: Count Number of Bad Pairs Solution
Master LeetCode problem 2364 (Count Number of Bad Pairs), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
2364. Count Number of Bad Pairs
Problem Explanation
Explanation:
To solve this problem, we iterate through the array and for each pair of indices (i, j), we check if it forms a bad pair according to the given condition. We compare the differences between the indices and the differences between the values at those indices. If they are not equal, we increment a counter to keep track of the number of bad pairs. At the end, we return the total count of bad pairs found.
- Initialize a counter to keep track of bad pairs.
- Iterate through the array and for each pair of indices (i, j):
- Check if i < j and nums[j] - nums[i] is not equal to j - i.
- If the condition is met, increment the bad pair counter.
- Return the total count of bad pairs.
Time complexity: O(n) where n is the number of elements in the array. Space complexity: O(1)
Solution Code
class Solution {
public int countPairs(int[] nums) {
int count = 0;
for (int i = 0; i < nums.length; i++) {
for (int j = i + 1; j < nums.length; j++) {
if (i < j && nums[j] - nums[i] != j - i) {
count++;
}
}
}
return count;
}
}Try It Yourself
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