LeetCode 2373: Largest Local Values in a Matrix Solution
Master LeetCode problem 2373 (Largest Local Values in a Matrix), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
Problem Explanation
Explanation:
To solve this problem, we iterate over the matrix and for each 3x3 submatrix, we find the maximum value and store it in the result matrix. We start from the top-left corner of the grid and move right and down, updating the result matrix accordingly.
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Algorithm:
- Initialize an empty result matrix
maxLocalof size (n-2) x (n-2). - Iterate over the grid matrix up to (n-2) x (n-2) submatrices.
- For each 3x3 submatrix, find the maximum value and store it in the
maxLocalmatrix. - Return the
maxLocalmatrix as the output.
- Initialize an empty result matrix
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Time Complexity: O(n^2) where n is the size of the input matrix.
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Space Complexity: O(1) excluding the space required for the output matrix.
Solution Code
class Solution {
public int[][] maxLocalValues(int[][] grid) {
int n = grid.length;
int[][] maxLocal = new int[n - 2][n - 2];
for (int i = 0; i < n - 2; i++) {
for (int j = 0; j < n - 2; j++) {
int max = Integer.MIN_VALUE;
for (int k = i; k < i + 3; k++) {
for (int l = j; l < j + 3; l++) {
max = Math.max(max, grid[k][l]);
}
}
maxLocal[i][j] = max;
}
}
return maxLocal;
}
}Try It Yourself
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