LeetCode 2380: Time Needed to Rearrange a Binary String Solution
Master LeetCode problem 2380 (Time Needed to Rearrange a Binary String), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
2380. Time Needed to Rearrange a Binary String
Problem Explanation
Explanation
To solve this problem, we can simulate the process of replacing "01" with "10" in the binary string until no more occurrences exist. We can iterate through the string and keep track of the number of seconds needed to complete the process.
- Iterate through the string and whenever we find "01", replace it with "10".
- Repeat this process until no more occurrences of "01" exist.
- Count the number of iterations needed, which represents the number of seconds required to rearrange the binary string.
Time Complexity: O(n) where n is the length of the input binary string. Space Complexity: O(1)
Solution Code
class Solution {
public int rearrangeBinaryString(String s) {
int seconds = 0;
while (s.contains("01")) {
s = s.replace("01", "10");
seconds++;
}
return seconds;
}
}Try It Yourself
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