LeetCode 2410: Maximum Matching of Players With Trainers Solution

Master LeetCode problem 2410 (Maximum Matching of Players With Trainers), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2410. Maximum Matching of Players With Trainers

Medium

Array Two Pointers Greedy Sorting

Problem Explanation

Explanation:

To maximize the number of matchings between players and trainers, we can sort both the players and trainers arrays in ascending order. Then, we can iterate through the sorted arrays and try to match players with trainers based on their abilities and training capacities. If a player's ability is less than or equal to a trainer's training capacity, we can increment the count of matchings and move on to the next player. This greedy approach ensures that we make the best possible matchings.

Algorithm:

Sort the players and trainers arrays in ascending order.
Initialize variables matchingCount to store the number of matchings and trainerIndex to keep track of the current trainer being considered.
Iterate through the players array and for each player, iterate through the trainers array starting from the trainerIndex.
If a player can be matched with a trainer, increment matchingCount and update trainerIndex to move to the next trainer.
Return the matchingCount as the maximum number of matchings.

Time Complexity: O(n log n), where n is the total number of players and trainers combined due to sorting.

Space Complexity: O(1) as we are using a constant amount of extra space.

Solution Code

class Solution {
    public int maxMatchings(int[] players, int[] trainers) {
        Arrays.sort(players);
        Arrays.sort(trainers);
        
        int matchingCount = 0;
        int trainerIndex = 0;
        
        for (int player : players) {
            while (trainerIndex < trainers.length && trainers[trainerIndex] < player) {
                trainerIndex++;
            }
            if (trainerIndex < trainers.length) {
                matchingCount++;
                trainerIndex++;
            }
        }
        
        return matchingCount;
    }
}

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