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LeetCode 2412: Minimum Money Required Before Transactions

ArrayGreedySorting

LeetCode 2412 Solution Explanation

Explanation:

To find the minimum amount of money required before any transaction so that all transactions can be completed regardless of the order, we can use a greedy approach. We need to consider the transactions with the highest cost first, as these will require the most money to complete.

  1. Sort the transactions array in descending order based on the difference between cost and cashback.
  2. Initialize a variable money to keep track of the total money required.
  3. Iterate through the sorted transactions array and update the money variable accordingly.

LeetCode 2412 Solutions in Java, C++, Python

import java.util.Arrays;

class Solution {
    public int minMoneyRequired(int[][] transactions) {
        Arrays.sort(transactions, (a, b) -> (b[0] - b[1]) - (a[0] - a[1]));
        int money = 0;
        for (int[] transaction : transactions) {
            money = Math.max(money, transaction[0]) + transaction[1];
        }
        return money;
    }
}

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