LeetCode 2419: Longest Subarray With Maximum Bitwise AND Solution

Master LeetCode problem 2419 (Longest Subarray With Maximum Bitwise AND), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2419. Longest Subarray With Maximum Bitwise AND

Medium

Array Bit Manipulation Brainteaser

Problem Explanation

Explanation:

To solve this problem, we can iterate through the array nums to find the maximum bitwise AND value k. Once we have k, we can iterate through the array again to find the longest subarray that has a bitwise AND equal to k. We can achieve this by keeping track of the start index of the current subarray and updating the length of the longest subarray when we encounter a bitwise AND equal to k.

Algorithmic Steps:

Iterate through nums to find the maximum bitwise AND value k.
Iterate through nums again to find the longest subarray with a bitwise AND equal to k.
Keep track of the start index of the current subarray and update the length of the longest subarray when necessary.

Time Complexity:

The time complexity of this approach is O(n), where n is the length of the input array nums.

Space Complexity:

The space complexity of this approach is O(1) as we are using a constant amount of extra space.

Solution Code

class Solution {
    public int longestSubarray(int[] nums) {
        int maxBitwiseAND = 0;
        for (int num : nums) {
            maxBitwiseAND = Math.max(maxBitwiseAND, num);
        }
        
        int start = 0;
        int maxLength = 0;
        for (int i = 0; i < nums.length; i++) {
            if ((nums[i] & maxBitwiseAND) != maxBitwiseAND) {
                maxLength = Math.max(maxLength, i - start);
                start = i;
            }
        }
        
        return Math.max(maxLength, nums.length - start);
    }
}

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