LeetCode 2425: Bitwise XOR of All Pairings Solution
Master LeetCode problem 2425 (Bitwise XOR of All Pairings), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
2425. Bitwise XOR of All Pairings
Problem Explanation
Explanation
To solve this problem, we can iterate over each pair of elements from nums1 and nums2, calculate their XOR, and keep updating the result by XORing it with the current pair's XOR value. This way, we can obtain the final XOR value of all pairings.
Time Complexity
The time complexity of this approach is O(n * m), where n is the length of nums1 and m is the length of nums2.
Space Complexity
The space complexity is O(1) as we are not using any extra space other than a few variables.
Solution Code
class Solution {
public int xorAllPairings(int[] nums1, int[] nums2) {
int xorResult = 0;
for (int num1 : nums1) {
for (int num2 : nums2) {
xorResult ^= (num1 ^ num2);
}
}
return xorResult;
}
}Try It Yourself
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What is the time complexity of LeetCode 2425 (Bitwise XOR of All Pairings)?
The time complexity for LeetCode 2425 (Bitwise XOR of All Pairings) varies by solution. Check the detailed explanation section for specific complexities in Java, C++, and Python implementations.
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