2451. Odd String Difference
Explanation
To solve this problem, we need to find the string in the input array that has a different difference integer array compared to the others. We can achieve this by calculating the difference integer array for each string in the input array and then checking for any differences.
- Calculate the difference integer array for each string.
- Compare the difference integer arrays of all strings to find the odd one out.
- Return the string corresponding to the odd difference integer array.
Time complexity: O(n) where n is the number of strings in the input array. Space complexity: O(n) for storing the difference integer arrays.
class Solution {
public String findOddString(String[] words) {
int n = words[0].length();
int[][] differences = new int[words.length][n - 1];
for (int i = 0; i < words.length; i++) {
for (int j = 0; j < n - 1; j++) {
differences[i][j] = words[i].charAt(j + 1) - words[i].charAt(j);
}
}
for (int i = 0; i < n - 1; i++) {
boolean isOdd = true;
for (int j = 1; j < words.length; j++) {
if (differences[j][i] != differences[0][i]) {
isOdd = false;
break;
}
}
if (isOdd) {
return words[i];
}
}
return ""; // No odd string found
}
}Code Editor (Testing phase)
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