LeetCode 2455: Average Value of Even Numbers That Are Divisible by Three Solution

Master LeetCode problem 2455 (Average Value of Even Numbers That Are Divisible by Three), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2455. Average Value of Even Numbers That Are Divisible by Three

Easy

Array Math

Problem Explanation

Explanation:

To solve this problem, we iterate through the given array nums and check if each even number is divisible by 3. If it is, we add it to our running sum and keep track of the count of such numbers. Finally, we return the integer division of the sum by the count. If no even number is found that satisfies the condition, we return 0.

Algorithm:

Initialize variables sum and count to 0.
Iterate through each element num in the array nums.
Check if num is even and divisible by 3.
If the condition is satisfied, add num to sum and increment count.
After iterating through all elements, return sum / count if count is greater than 0, else return 0.

Time Complexity: O(n), where n is the number of elements in the input array. Space Complexity: O(1)

Solution Code

class Solution {
    public int averageEvenDivByThree(int[] nums) {
        int sum = 0;
        int count = 0;
        
        for (int num : nums) {
            if (num % 2 == 0 && num % 3 == 0) {
                sum += num;
                count++;
            }
        }
        
        return count > 0 ? sum / count : 0;
    }
}

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