LeetCode 2465: Number of Distinct Averages Solution

Master LeetCode problem 2465 (Number of Distinct Averages), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2465. Number of Distinct Averages

Easy

Array Hash Table Two Pointers Sorting

Problem Explanation

Explanation

To solve this problem, we can iterate through all possible pairs of numbers in the array, calculate their average, and store the distinct averages in a set. Once we have processed all pairs, the size of the set will give us the number of distinct averages.

We start by initializing a set to store the distinct averages.
We iterate through all pairs of numbers in the array (using two nested loops).
For each pair, we calculate the average and add it to the set.
Finally, we return the size of the set as the number of distinct averages.

Time Complexity: O(n^2) where n is the number of elements in the input array. Space Complexity: O(n) to store the distinct averages.

Solution Code

class Solution {
    public int numberOfDistinctAverages(int[] nums) {
        Set<Double> distinctAverages = new HashSet<>();
        
        for (int i = 0; i < nums.length; i++) {
            for (int j = i + 1; j < nums.length; j++) {
                double average = (nums[i] + nums[j]) / 2.0;
                distinctAverages.add(average);
            }
        }
        
        return distinctAverages.size();
    }
}

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