LeetCode 2468: Split Message Based on Limit Solution

Master LeetCode problem 2468 (Split Message Based on Limit), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2468. Split Message Based on Limit

Hard

String Binary Search Enumeration

Problem Explanation

Explanation

To solve this problem, we can iterate through the message while keeping track of the current part. We need to split the message into parts of length limit or less, and each part should have a suffix indicating its index and the total number of parts. We can achieve this by determining the number of parts needed, then dividing the message into equal parts (except the last one) and adjusting the length of the last part if necessary. Finally, we construct the parts with the appropriate suffixes.

Calculate the number of parts needed: numParts = ceiling(message.length() / limit).
Iterate over the message, splitting it into parts of length limit (except the last part).
Append the parts with the correct suffixes to the result array.

Time complexity: O(n) where n is the length of the message
Space complexity: O(n) for the result array

Solution Code

class Solution {
    public String[] splitMessage(String message, int limit) {
        int numParts = (int) Math.ceil((double) message.length() / limit);
        String[] result = new String[numParts];
        
        int index = 0;
        for (int i = 0; i < numParts - 1; i++) {
            result[i] = message.substring(index, index + limit) + "<" + (i + 1) + "/" + numParts + ">";
            index += limit;
        }
        
        result[numParts - 1] = message.substring(index) + "<" + numParts + "/" + numParts + ">";
        
        return result;
    }
}

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