LeetCode 2491: Divide Players Into Teams of Equal Skill Solution

Master LeetCode problem 2491 (Divide Players Into Teams of Equal Skill), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2491. Divide Players Into Teams of Equal Skill

Medium

Array Hash Table Two Pointers Sorting

Problem Explanation

Explanation:

To solve this problem, we can follow these steps:

Calculate the total sum of all player skills in the array.
Sort the array of player skills in non-decreasing order.
Iterate over the array, trying to pair players from the extremes (highest and lowest skills) to form teams with equal total skill.
Calculate the chemistry of each team and sum them up. If all teams have the same total skill, return the sum of chemistry. Otherwise, return -1.

Time Complexity: Sorting the array takes O(nlogn) time. After sorting, iterating over the array takes O(n) time. So, the overall time complexity is O(nlogn).

Space Complexity: We are not using any extra space other than a few variables. Thus, the space complexity is O(1).

Solution Code

class Solution {
    public int dividePlayersIntoTeams(int[] skill) {
        int n = skill.length;
        if (n % 2 != 0) {
            return -1; // Return -1 if the number of players is odd
        }
        
        Arrays.sort(skill);
        
        int sum = 0;
        for (int i = 0; i < n/2; i++) {
            sum += skill[i] * skill[n-1-i];
        }
        
        return sum;
    }
}

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