LeetCode 2505: Bitwise OR of All Subsequence Sums
LeetCode 2505 Solution Explanation
Explanation
The problem asks us to find the bitwise OR of all possible subsequence sums of a given array. A subsequence is a sequence that can be derived from another sequence by deleting some elements without changing the order of the remaining elements.
To solve this problem, we can iterate through all possible subsequences of the given array and calculate the sum of each subsequence. Then, we bitwise OR all these sums together to get the final result.
Algorithm:
- Initialize a variable
resultto store the final bitwise OR result. - Iterate through all possible subsequences of the input array using bit manipulation.
- For each subsequence, calculate the sum of its elements and bitwise OR it with
result. - Return the final
result.
Time Complexity: O(2^N * N) where N is the number of elements in the input array. Space Complexity: O(1)
LeetCode 2505 Solutions in Java, C++, Python
class Solution {
public int subarrayBitwiseORs(int[] arr) {
Set<Integer> res = new HashSet<>();
Set<Integer> cur = new HashSet<>();
Set<Integer> next;
for (int num : arr) {
next = new HashSet<>();
next.add(num);
for (int c : cur) {
next.add(c | num);
}
res.addAll(next);
cur = next;
}
return res.size();
}
}Interactive Code Editor for LeetCode 2505
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