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LeetCode 2514: Count Anagrams Solution

Master LeetCode problem 2514 (Count Anagrams), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

Problem Explanation

Explanation:

To solve this problem, we can follow these steps:

  1. Split the input string s into individual words.
  2. For each word in s, sort the characters to get a canonical representation of the word.
  3. Count the frequency of each canonical word.
  4. Calculate the number of distinct anagrams by multiplying the factorial of the counts of each canonical word.
  5. Return the result modulo 10^9 + 7.

Time Complexity: The time complexity of this approach is O(n * k * log(k)), where n is the number of words in the input string s and k is the average length of each word.

Space Complexity: The space complexity is O(n * k) to store the canonical representation of each word.

:

Solution Code

class Solution {
    public int countAnagrams(String s) {
        final int MOD = 1000000007;
        String[] words = s.split(" ");
        Map<String, Integer> wordCounts = new HashMap<>();
        
        for (String word : words) {
            char[] chars = word.toCharArray();
            Arrays.sort(chars);
            String canonical = new String(chars);
            wordCounts.put(canonical, wordCounts.getOrDefault(canonical, 0) + 1);
        }
        
        long result = 1;
        for (int count : wordCounts.values()) {
            result = (result * factorial(count)) % MOD;
        }
        
        return (int) result;
    }
    
    private long factorial(int n) {
        long result = 1;
        for (int i = 1; i <= n; i++) {
            result = (result * i) % 1000000007;
        }
        return result;
    }
}

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