LeetCode 2527: Find Xor-Beauty of Array Solution
Master LeetCode problem 2527 (Find Xor-Beauty of Array), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
2527. Find Xor-Beauty of Array
Problem Explanation
Explanation:
-
Algorithmic Idea:
- Iterate over all possible triplets of indices (i, j, k) in the array.
- Calculate the effective value of each triplet as ((nums[i] | nums[j]) & nums[k]).
- XOR all the effective values to get the xor-beauty of the array.
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Step-by-Step Iterations:
- For each triplet (i, j, k), calculate the effective value and XOR them to get the final result.
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Time Complexity: O(n^3) where n is the length of the input array.
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Space Complexity: O(1)
:
Solution Code
class Solution {
public int xorBeauty(int[] nums) {
int xorBeauty = 0;
int n = nums.length;
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
for (int k = 0; k < n; k++) {
xorBeauty ^= ((nums[i] | nums[j]) & nums[k]);
}
}
}
return xorBeauty;
}
}Try It Yourself
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