LeetCode 2555: Maximize Win From Two Segments
Problem Description
Explanation:
To solve this problem, we can iterate through all possible pairs of segments with length k and calculate the total number of prizes that can be won by selecting those two segments. We can keep track of the maximum number of prizes obtained from all possible pairs.
- Iterate through all possible pairs of segments with length
k. - For each pair, calculate the total number of prizes that can be won by considering the prizes within or intersecting the segments.
- Update the maximum number of prizes obtained so far.
Time Complexity: O(n^2) where n is the length of the input prizePositions.
Space Complexity: O(1) as we are using a constant amount of extra space.
:
Solutions
class Solution {
public int maximizeWinFromTwoSegments(int[] prizePositions, int k) {
int maxPrizes = 0;
for (int i = 0; i <= prizePositions.length - k; i++) {
for (int j = i + k; j < prizePositions.length; j++) {
int count = 0;
for (int pos : prizePositions) {
if ((pos >= prizePositions[i] && pos <= prizePositions[i] + k) ||
(pos >= prizePositions[j] && pos <= prizePositions[j] + k)) {
count++;
}
}
maxPrizes = Math.max(maxPrizes, count);
}
}
return maxPrizes;
}
}Loading editor...