LeetCode 2569: Handling Sum Queries After Update Solution

Master LeetCode problem 2569 (Handling Sum Queries After Update), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2569. Handling Sum Queries After Update

Hard

Array Segment Tree

Problem Explanation

Explanation

To solve this problem, we can simulate the queries and update the arrays nums1 and nums2 accordingly. For each query type:

For type 1 query, we flip the values in nums1 from index l to index r.
For type 2 query, we update nums2 by adding nums1[i] * p for all indices i.
For type 3 query, we find the sum of elements in nums2 and store it in the result array.

Solution Code

class Solution {
    public int[] handleSumQueries(int[] nums1, int[] nums2, int[][] queries) {
        int n = nums1.length;
        int[] result = new int[queries.length];
        
        for (int i = 0; i < queries.length; i++) {
            int[] query = queries[i];
            if (query[0] == 1) {
                for (int j = query[1]; j <= query[2]; j++) {
                    nums1[j] = 1 - nums1[j];
                }
            } else if (query[0] == 2) {
                for (int j = 0; j < n; j++) {
                    nums2[j] += nums1[j] * query[1];
                }
            } else {
                int sum = 0;
                for (int j = 0; j < n; j++) {
                    sum += nums2[j];
                }
                result[i] = sum;
            }
        }
        
        return result;
    }
}

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