LeetCode 2571: Minimum Operations to Reduce an Integer to 0 Solution

Master LeetCode problem 2571 (Minimum Operations to Reduce an Integer to 0), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2571. Minimum Operations to Reduce an Integer to 0

Medium

Dynamic Programming Greedy Bit Manipulation

Problem Explanation

Explanation

To solve this problem, we can start by repeatedly subtracting the largest power of 2 from the given number until it reaches 0. We can easily determine the largest power of 2 by finding the highest bit set in the binary representation of the number. The number of operations required will be equal to the count of set bits in the binary representation of the input number.

Algorithm:

Initialize a variable count to 0.
While the input number n is greater than 0:
- Find the highest bit set in n (which corresponds to the largest power of 2).
- Subtract that power of 2 from n.
- Increment count by 1.
Return the final value of count.

Time Complexity: The time complexity of this algorithm is O(log n), where n is the input number.

Space Complexity: The space complexity is O(1) as we are using a constant amount of extra space.

Solution Code

class Solution {
    public int minOperations(int n) {
        int count = 0;
        while (n > 0) {
            int largestPowerOf2 = Integer.highestOneBit(n);
            n -= largestPowerOf2;
            count++;
        }
        return count;
    }
}

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