LeetCode 2572: Count the Number of Square-Free Subsets Solution
Master LeetCode problem 2572 (Count the Number of Square-Free Subsets), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
2572. Count the Number of Square-Free Subsets
Problem Explanation
Explanation
To solve this problem, we can use dynamic programming. We need to find the number of square-free subsets in the given array. For any subset to be square-free, the product of its elements should not be divisible by any square number other than 1.
We can create a DP array where dp[i] represents the number of square-free subsets that can be formed using elements up to index i. We can then iterate through the array and update the dp array based on the current element and the previously calculated values.
The final answer will be the sum of all elements in the dp array modulo 10^9 + 7.
Time Complexity: O(n^2) where n is the number of elements in the array
Space Complexity: O(n)
Solution Code
class Solution {
public int countSquareFreeSubsets(int[] nums) {
int mod = 1000000007;
int n = nums.length;
long[] dp = new long[n];
long res = 0;
for (int i = 0; i < n; i++) {
dp[i] = 1;
for (int j = 0; j < i; j++) {
if ((dp[j] * nums[i]) % 4 != 0 && (dp[j] * nums[i]) % 9 != 0) {
dp[i] += dp[j];
dp[i] %= mod;
}
}
res += dp[i];
res %= mod;
}
return (int) res;
}
}Try It Yourself
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