LeetCode 2575: Find the Divisibility Array of a String Solution

Master LeetCode problem 2575 (Find the Divisibility Array of a String), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2575. Find the Divisibility Array of a String

Problem Explanation

Explanation:

To solve this problem, we iterate through the given string word from left to right, keeping track of the numeric value of the prefixes. At each step, we calculate the numeric value of the current prefix by multiplying the previous numeric value by 10 and adding the current digit. We then check if this numeric value is divisible by m and update the divisibility array accordingly.

  • We initialize the result array div with all zeros.
  • We iterate through the string word, updating the numeric value of the prefix at each step.
  • If the numeric value is divisible by m, we update the corresponding index in the div array to 1.

Time Complexity: O(n), where n is the length of the input string word. Space Complexity: O(n), for storing the divisibility array.

Solution Code

public int[] findDivisibilityArray(String word, int m) {
    int n = word.length();
    int[] div = new int[n];
    int num = 0;
    
    for (int i = 0; i < n; i++) {
        num = (num * 10 + (word.charAt(i) - '0')) % m;
        if (num == 0) {
            div[i] = 1;
        }
    }
    
    return div;
}

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