LeetCode 2589: Minimum Time to Complete All Tasks Solution
Master LeetCode problem 2589 (Minimum Time to Complete All Tasks), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
2589. Minimum Time to Complete All Tasks
Problem Explanation
Explanation
To solve this problem, we need to find the minimum time during which the computer should be turned on to complete all tasks. We can achieve this by iterating over the tasks and calculating the total time needed to complete each task. We can then find the total time the computer needs to be turned on by considering the intervals where tasks are running.
- Sort the tasks based on their end times.
- Initialize variables
timeOn
andprevEnd
to track the current time the computer is turned on and the end time of the previous task. - Iterate through the sorted tasks.
- For each task:
- If the task's start time is greater than the
prevEnd
, updatetimeOn
to include the duration of the current task. - Else, update
timeOn
by adding the difference between the current task's end time and theprevEnd
. - Update
prevEnd
to the end time of the current task.
- If the task's start time is greater than the
- Return the final
timeOn
as the minimum time the computer needs to be turned on.
Time Complexity: O(n log n) where n is the number of tasks. Sorting the tasks takes O(n log n) time.
Space Complexity: O(1) as we are using constant extra space.
Solution Code
class Solution {
public int minTimeToCompleteAllTasks(int[][] tasks) {
Arrays.sort(tasks, (a, b) -> a[1] - b[1]);
int timeOn = 0, prevEnd = -1;
for (int[] task : tasks) {
if (task[0] > prevEnd) {
timeOn += task[2];
} else {
timeOn += task[2] - (prevEnd - task[0]);
}
prevEnd = task[1];
}
return timeOn;
}
}
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