LeetCode 2594: Minimum Time to Repair Cars Solution

Master LeetCode problem 2594 (Minimum Time to Repair Cars), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2594. Minimum Time to Repair Cars

Problem Explanation

Explanation:

To minimize the time taken to repair all cars, we need to assign cars to mechanics in a way that minimizes the overall time. We can achieve this by assigning cars to mechanics with the lowest ranks first, as they are the most efficient in terms of repair time per car.

  1. Sort the mechanics based on their ranks in non-decreasing order.
  2. Initialize a variable totalTime to store the total time taken to repair all cars.
  3. Iterate over the sorted mechanics:
    • Calculate the number of cars that can be assigned to the current mechanic based on their rank and the total number of cars left to be repaired.
    • Update totalTime by adding the time taken by the current mechanic to repair the assigned cars.
  4. Return totalTime as the minimum time taken to repair all cars.

Time Complexity: Sorting the mechanics takes O(n log n) time, where n is the number of mechanics. The subsequent iteration takes O(n) time. Thus, the overall time complexity is O(n log n).

Space Complexity: We use additional space for sorting the mechanics, resulting in O(n) space complexity.

:

Solution Code

class Solution {
    public int minTimeToRepairCars(int[] ranks, int cars) {
        Arrays.sort(ranks);
        int totalTime = 0;
        int i = 0;
        
        while (cars > 0) {
            int numCars = Math.min(ranks[i], cars);
            totalTime += ranks[i] * numCars * numCars;
            cars -= numCars;
            i++;
        }
        
        return totalTime;
    }
}

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