LeetCode 2597: The Number of Beautiful Subsets Solution
Master LeetCode problem 2597 (The Number of Beautiful Subsets), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
2597. The Number of Beautiful Subsets
Problem Explanation
Explanation:
To solve this problem, we can use dynamic programming to count the number of beautiful subsets. We can define a state dp[mask][last] which represents the number of beautiful subsets of the array nums where the subset has elements represented by the bits set in mask, and the last element selected is nums[last]. We can then iterate over all possible subsets and calculate the count while taking care not to violate the condition of absolute difference equal to k.
Algorithmic Idea:
- Initialize a 2D array
dp[mask][last]wheremaskrepresents the subset andlastrepresents the last element chosen. - Iterate over all possible subsets and for each subset, iterate over all elements in the subset to calculate the count of beautiful subsets.
- Use dynamic programming to update the count based on the condition of absolute difference
k. - Finally, return the total count of beautiful subsets.
Time Complexity:
The time complexity of this solution is O(2^n * n) where n is the length of the input array nums.
Space Complexity:
The space complexity of this solution is O(2^n).
:
Solution Code
class Solution {
public int countBeautifulSubsets(int[] nums, int k) {
int n = nums.length;
int[][] dp = new int[1 << n][n];
for (int i = 0; i < n; i++) {
dp[1 << i][i] = 1;
}
for (int mask = 0; mask < (1 << n); mask++) {
for (int last = 0; last < n; last++) {
if (dp[mask][last] == 0) continue;
for (int i = 0; i < n; i++) {
if ((mask & (1 << i)) == 0 && Math.abs(nums[i] - nums[last]) != k) {
dp[mask | (1 << i)][i] += dp[mask][last];
}
}
}
}
int res = 0;
for (int mask = 1; mask < (1 << n); mask++) {
for (int i = 0; i < n; i++) {
res += dp[mask][i];
}
}
return res;
}
}Try It Yourself
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