LeetCode 2600: K Items With the Maximum Sum Solution

Master LeetCode problem 2600 (K Items With the Maximum Sum), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2600. K Items With the Maximum Sum

Easy

Math Greedy

Problem Explanation

Explanation

To maximize the sum of items picked, we should prioritize selecting items with values 1, then 0, and finally -1. We can achieve this by iterating through the items in descending order of values and selecting items accordingly until we reach the required count k.

Initialize a variable sum to 0 to store the total sum of selected items.
Iterate through the items in descending order of values.
Select items with value 1 first until k items are selected or no more 1s are available.
If k items are not fulfilled, select items with value 0 next until k items are selected or no more 0s are available.
If k items are still not fulfilled, select items with value -1 until k items are selected or no more -1s are available.
Return the final sum.

Time Complexity: O(n), where n is the total number of items available in the bag. Space Complexity: O(1)

Solution Code

class Solution {
    public int maxItems(int numOnes, int numZeros, int numNegOnes, int k) {
        int sum = 0;
        int count = 0;
        
        while (count < k) {
            if (numOnes > 0) {
                sum += 1;
                numOnes--;
            } else if (numZeros > 0) {
                sum += 0;
                numZeros--;
            } else {
                sum += -1;
                numNegOnes--;
            }
            count++;
        }
        
        return sum;
    }
}

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