LeetCode 2602: Minimum Operations to Make All Array Elements Equal Solution

Master LeetCode problem 2602 (Minimum Operations to Make All Array Elements Equal), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2602. Minimum Operations to Make All Array Elements Equal

Medium

Array Binary Search Sorting Prefix Sum

Problem Explanation

Explanation:

To solve this problem, we need to find the minimum number of operations required to make all elements of the array equal to each query value. We can do this by calculating the sum of absolute differences between each element of the array and the query value. The sum of these absolute differences will give us the total number of operations needed to make all elements equal to the query value.

Algorithm:

Iterate through each query value.
For each query value, calculate the sum of absolute differences between each element in the array and the query value.
Add this sum to the answer array.
Repeat steps 2 and 3 for all query values.

Time Complexity:

The time complexity of this algorithm is O(n * m), where n is the number of elements in the array and m is the number of queries.

Space Complexity:

The space complexity of this algorithm is O(m), where m is the number of queries.

Solution Code

class Solution {
    public int[] minOperations(int[] nums, int[] queries) {
        int n = nums.length;
        int m = queries.length;
        int[] answer = new int[m];
        
        for (int i = 0; i < m; i++) {
            int sum = 0;
            for (int j = 0; j < n; j++) {
                sum += Math.abs(nums[j] - queries[i]);
            }
            answer[i] = sum;
        }
        
        return answer;
    }
}

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