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LeetCode 2610: Convert an Array Into a 2D Array With Conditions Solution

Master LeetCode problem 2610 (Convert an Array Into a 2D Array With Conditions), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2610. Convert an Array Into a 2D Array With Conditions

Medium
ArrayHash Table

Problem Explanation

Explanation

To solve this problem, we can follow the steps below:

  1. Sort the input array nums in descending order.
  2. Create a 2D array result where each row will contain distinct elements from nums.
  3. Iterate through the sorted nums array and distribute elements into rows such that each row contains distinct elements.
  4. Return the resulting 2D array.

The time complexity of this approach is O(nlogn) due to sorting, where n is the number of elements in the input array nums. The space complexity is O(n) to store the resulting 2D array.

Solution Code

import java.util.*;

class Solution {
    public List<List<Integer>> convert2DArray(int[] nums) {
        Arrays.sort(nums);
        List<List<Integer>> result = new ArrayList<>();
        for (int num : nums) {
            if (result.isEmpty() || result.get(result.size() - 1).contains(num)) {
                result.add(new ArrayList<>(Arrays.asList(num)));
            } else {
                result.get(result.size() - 1).add(num);
            }
        }
        return result;
    }
}

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