LeetCode 2615: Sum of Distances Solution

Master LeetCode problem 2615 (Sum of Distances), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2615. Sum of Distances

Medium

Array Hash Table Prefix Sum

Problem Explanation

Explanation

To solve this problem, we can iterate through the given array nums and for each element nums[i], we find the sum of distances from i to all other indices j where nums[j] == nums[i] and j != i. We can calculate this sum by iterating through the array again and summing the absolute differences of indices for matching values.

Algorithm:

Initialize an array arr of the same length as nums to store the final results.
Iterate through each element in nums:
- For each element nums[i], iterate through the array again to find matching values.
- Calculate the sum of distances for each matching value and add it to arr[i].
Return the final array arr.

Time Complexity:

The time complexity of this solution is O(n^2), where n is the length of the input array nums.

Space Complexity:

The space complexity of this solution is O(n) to store the final array arr.

Solution Code

class Solution {
    public int[] sumOfDistancesInArray(int[] nums) {
        int n = nums.length;
        int[] arr = new int[n];

        for (int i = 0; i < n; i++) {
            for (int j = 0; j < n; j++) {
                if (nums[j] == nums[i] && j != i) {
                    arr[i] += Math.abs(j - i);
                }
            }
        }

        return arr;
    }
}

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