LeetCode 2623: Memoize Solution

Master LeetCode problem 2623 (Memoize), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2623. Memoize

Medium

Problem Explanation

Explanation:

To solve this problem, we need to implement a memoization technique where we cache the results of function calls to avoid redundant calculations. The cache will store the results of function calls based on their input arguments. If the same input arguments are received again, we can directly return the cached result instead of recalculating it.

For this problem, we are given three possible input functions: sum, fib, and factorial. We need to memoize these functions based on the input arguments provided.

We can use a HashMap to store the cached results where the key is a unique identifier for the input arguments, and the value is the result of the function call. When a function is called, we check if the result for the given input arguments already exists in the cache. If it does, we return the cached result; otherwise, we calculate the result, store it in the cache, and return it.

Time Complexity:

The time complexity for each function call will be O(1) on average since we are using memoization to store and retrieve results.

Space Complexity:

The space complexity will depend on the number of unique function calls made and the size of the cache required to store the results.

Solution Code

import java.util.HashMap;
import java.util.Map;

class Memoize {
    Map<String, Integer> cache;

    public Memoize() {
        this.cache = new HashMap<>();
    }

    public int memoize(String fnName, int[] args) {
        String key = fnName + args[0] + "_" + args[1]; // Unique key based on function name and arguments

        if (cache.containsKey(key)) {
            return cache.get(key);
        }

        int result = 0;
        switch (fnName) {
            case "sum":
                result = args[0] + args[1];
                break;
            case "fib":
                result = (args[0] <= 1) ? 1 : memoize("fib", new int[]{args[0] - 1}) + memoize("fib", new int[]{args[0] - 2});
                break;
            case "factorial":
                result = (args[0] <= 1) ? 1 : args[0] * memoize("factorial", new int[]{args[0] - 1});
                break;
        }

        cache.put(key, result);
        return result;
    }
}

Try It Yourself

Loading code editor...

Frequently Asked Questions

How to solve LeetCode 2623 (Memoize)?

This page provides optimized solutions for LeetCode problem 2623 (Memoize) in Java, C++, and Python, along with a detailed explanation and an interactive code editor to test your code.

What is the time complexity of LeetCode 2623 (Memoize)?

The time complexity for LeetCode 2623 (Memoize) varies by solution. Check the detailed explanation section for specific complexities in Java, C++, and Python implementations.

Can I run code for LeetCode 2623 on DevExCode?

Yes, DevExCode provides an interactive code editor where you can write, test, and run your code for LeetCode 2623 in Java, C++, or Python.

Back to LeetCode Solutions